7x-3y=4 2x-4y=1 Which of the following systems is not the same as solving the system shown? 28x-12y=16 and -6x+12y=-3 -28x+12y=-16 and 28x-56y=14 14x-6y=4 and -14x+28y=1

To determine which system of equations is not equivalent to the given system, we need to compare each option with the original system.<br /><br />The given system is:<br />$7x-3y=4$<br />$2x-4y=1$<br /><br />Let's analyze each option:<br /><br />Option 1: $28x-12y=16$ and $-6x+12y=-3$<br />If we multiply the first equation of the given system by 4, we get $28x-12y=16$, which matches the first equation in Option 1. However, the second equation in Option 1 does not match the second equation in the given system when multiplied by -3. Therefore, Option is not equivalent to the given system.<br /><br />Option 2: $-28x+12y=-16$ and $28x-56y=14$<br />If we multiply the first equation of the given system by -4, we get $-28x+12y=-16$, which matches the first equation in Option 2. However, the second equation in Option 2 does not match the second equation in the given system when multiplied by 14. Therefore, Option 2 is not equivalent to the given system.<br /><br />Option 3: $14x-6y=4$ and $-+28y=1$<br />If we multiply the first equation of the given system by 2, we get $14x-6y=4$, which matches the first equation in Option 3. If we multiply the second equation of the given system by -7, we get $-14x+28y=1$, which matches the second equation in Option 3. Therefore, Option 3 is equivalent to the given system.<br /><br />Based on our analysis, the system that is not equivalent to the given system is Option 1: $28x-12y=16$ and $-6x+12y=-3$.