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square (3y^3)(-2y^2)= square (-12v^5)/(3v^5)= square (-4z^3)^2= square (-64y^6)/(-8y^2)= square

Problemas

square 
(3y^3)(-2y^2)=
square 
(-12v^5)/(3v^5)=
square 
(-4z^3)^2=
square 
(-64y^6)/(-8y^2)=
square

square (3y^3)(-2y^2)= square (-12v^5)/(3v^5)= square (-4z^3)^2= square (-64y^6)/(-8y^2)= square

Solución

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Esthermaestro · Tutor durante 5 años
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$(3y^{3})(-2y^{2}) = -6y^{5}$<br /><br />$\frac {-12v^{5}}{3v^{5}} = -4$<br /><br />$(-4z^{3})^{2} = 16z^{6}$<br /><br />$\frac {-64y^{6}}{-8y^{2}} = 8y^{4}$
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