Put the quadratic into vertex form and state the coordinates of the vertex. y=x^2-10x+9 Answer Vertex Form: y=square Vertex: (square ,square )

To put the quadratic equation into vertex form, we need to complete the square.<br /><br />Given equation: $y = x^2 - 10x + 9$<br /><br />Step 1: Factor out the coefficient of $x^2$ from the first two terms.<br />$y = (x^2 - 10x) + 9$<br /><br />Step 2: Complete the square by adding and subtracting the square of half the coefficient of $x$ inside the parentheses.<br />$y = (x^2 - 10x + 25) - 25 + 9$<br />$y = (x - 5)^2 - 16$<br /><br />Therefore, the vertex form of the quadratic equation is:<br />$y = (x - 5)^2 - 16$<br /><br />The coordinates of the vertex are:<br />Vertex: $(5, -16)$