Solve the following system of equations. 3x+2y-5=0 x=y+10 Make sure there are NO SPACES in your answer. Include a comma in your answer. ANSWER: [( square 1)

To solve the system of equations, we can use substitution or elimination. In this case, we can substitute the second equation into the first equation.<br /><br />Substituting $x = y + 10$ into the first equation, we get:<br /><br />$3(y + 10) + 2y - 5 = 0$<br /><br />Simplifying, we have:<br /><br />$3y + 30 + 2y - 5 = 0$<br /><br />$5y + 25 = 0$<br /><br />$5y = -25$<br /><br />$y = -5$<br /><br />Now that we have the value of $y$, we can substitute it back into the second equation to find the value of $x$:<br /><br />$x = y + 10$<br /><br />$x = -5 + 10$<br /><br />$x = 5$<br /><br />Therefore, the solution to the system of equations is $(5,-5)$.