Graph the function Identify the axis of symmetry and the vertex. f(x)=x^2-4x+7 The axis of symmetry is square (Type an equation.)

## Step 1<br />The given function is a quadratic function in the form \(f(x) = ax^2 + bx + c\), where \(a = 1\), \(b = -4\), and \(c = 7\).<br /><br />## Step 2<br />The axis of symmetry for a quadratic function is given by the formula \(x = -\frac{b}{2a}\).<br /><br />### **The formula for the axis of symmetry is \(x = -\frac{b}{2a}\)**<br /><br />## Step 3<br />Substitute the values of \(a\) and \(b\) into the formula to find the axis of symmetry.<br /><br />## Step 4<br />The vertex of the parabola is the point on the axis of symmetry that is also on the graph of the function. It is given by the point \((-\frac{b}{2a}, f(-\frac{b}{2a}))\).<br /><br />### **The formula for the vertex is \((-\frac{b}{2a}, f(-\frac{b}{2a}))\)**<br /><br />## Step 5<br />Substitute the values of \(a\), \(b\), and \(c\) into the formula to find the vertex.