Use a calculator to solve the equation on the interval [0,2pi ) sinx=0.7821 What are the solutions in the interval [0,2pi ) Select the correct choice below and, if necessary.fill in the answer box to complete your cho A. x=square (Type your answer in radians. Round to four decimal places as needed Use a comma to separate answers as needed.) B. There is no solution.

To solve the equation $\sin x = 0.7821$ on the interval $[0, 2\pi)$, we need to find the values of $x$ for which the sine function equals 0.7821.<br /><br />The sine function is positive in the first and second quadrants. Therefore, we need to find the angles in these quadrants where the sine value is 0.7821.<br /><br />Using a calculator, we can find the inverse sine of 0.7821:<br />$\sin^{-1}(0.7821) \approx 0.9273$ radians<br /><br />Since the sine function is positive in the first and second quadrants, we can write the solutions as:<br />$x_1 = 0.9273$<br />$x_2 = \pi - 0.9273$<br /><br />Therefore, the solutions to the equation $\sin x = 0.7821$ on the interval $[0, 2\pi)$ are:<br />A. $x = 0.9273, \pi - 0.9273$