Solve the following system of equations by the substitution method. 10x+10y=1 x=y-3 What is the value of y? -3/2 -29/20 31/20

To solve the system of equations by the substitution method, we can substitute the expression for x from the second equation into the first equation.<br /><br />Given:<br />$10x + 10y = 1$<br />$x = y - 3$<br /><br />Substitute the expression for x into the first equation:<br />$10(y - 3) + 10y = 1$<br /><br />Simplify the equation:<br />$10y - 30 + 10y = 1$<br />$20y - 30 = 1$<br />$20y = 31$<br />$y = \frac{31}{20}$<br /><br />Therefore, the value of y is $\frac{31}{20}$.