Solve the following . observing significant figure rules 110.10g+13g+0.656g square 9

To solve the problem while observing significant figure rules, we need to consider the number of decimal places in each measurement.<br /><br />1. **Addition:**<br /> - \(110.10 \, \text{g}\) has two decimal places.<br /> - \(13 \, \text{g}\) is a whole number with zero decimal places.<br /> - \(0.656 \, \text{g}\) has three decimal places.<br /><br />When adding numbers, the result should be reported with the same number of decimal places as the measurement with the fewest decimal places. In this case, that is zero decimal places (from 13 g).<br /><br />Perform the addition:<br /><br />\[ <br />110.10 \, \text{g} + 13 \, \text{g} + 0.656 \, \text{g} = 123.756 \, \text{g}<br />\]<br /><br />Since the measurement with the fewest decimal places has zero decimal places, we round 123.756 to the nearest whole number:<br /><br />\[ <br />123.756 \approx 124 \, \text{g}<br />\]<br /><br />2. **Multiplication by 9:**<br /><br />Now, multiply the rounded sum by 9:<br /><br />\[ <br />124 \times 9 = 1116<br />\]<br /><br />The multiplication does not affect the significant figures from the addition step because 9 is an exact number (it can be considered to have infinite significant figures). Therefore, the final answer remains:<br /><br />\[ <br />1116<br />\]<br /><br />Thus, the final result, considering significant figures, is:<br /><br />\[ <br />1116<br />\]