Question Point S is on line segment overline (RT) Given ST=2x-10,RS=2x-5 and i RT=3x+1 determine the numerical length of overline (RT) Answer Attemptiout of a RT=square

## Step 1<br />We are given that point S is on line segment RT. This implies that the sum of the lengths of RS and ST equals the length of RT. This can be represented by the equation:<br />### \(RS + ST = RT\)<br /><br />## Step 2<br />We are given the expressions for RS, ST, and RT as \(2x-5\), \(2x-10\), and \(3x+1\) respectively. Substituting these expressions into the equation from Step 1, we get:<br />### \((2x-5) + (2x-10) = 3x+1\)<br /><br />## Step 3<br />Next, we simplify the equation by combining like terms on the left side of the equation. This gives us:<br />### \(4x - 15 = 3x + 1\)<br /><br />## Step 4<br />To solve for x, we subtract \(3x\) from both sides of the equation, which gives us:<br />### \(x = 16\)<br /><br />## Step 5<br />Finally, we substitute \(x = 16\) into the expression for RT, \(3x+1\), to find the numerical length of RT. This gives us:<br />### \(RT = 3*16 + 1 = 49\)