Solve the equation Determine whether the equation has one solution. no solution, or infinitely many solutions. 3. 5n=-20 4. g+5=17 5. 13+3p+10=23+3p 6 7+4y=39 7. 3=t+11.5-t 8. 4x+8+6x-5=33 9 5(2c+7)-3c=7(c+5) 10 (3)/(2)b+6+(1)/(2)b=15+2b

3. To solve the equation $5n=-20$, we need to isolate the variable $n$. We can do this by dividing both sides of the equation by 5:<br /><br />$5n = -20$<br /><br />$n = \frac{-20}{5}$<br /><br />$n = -4$<br /><br />Therefore, the equation has one solution: $n = -4$.<br /><br />4. To solve the equation $g+5=17$, we need to isolate the variable $g$. We can do this by subtracting 5 from both sides of the equation:<br /><br />$g+5 = 17$<br /><br />$g = 17 - 5$<br /><br />$g = 12$<br /><br />Therefore, the equation has one solution: $g = 12$.<br /><br />5. To solve the equation $13+3p+10=23+3p$, we need to simplify both sides of the equation and then isolate the variable $p$. <br /><br />$13+3p+10 = 23+3p$<br /><br />$23+3p = 23+3p$<br /><br />Since both sides of the equation are equal, this equation has infinitely many solutions.<br /><br />6. To solve the equation $7+4y=39$, we need to isolate the variable $y$. We can do this by subtracting 7 from both sides of the equation and then dividing both sides by 4:<br /><br />$7+4y = 39$<br /><br />$4y = 39 - 7$<br /><br />$4y = 32$<br /><br />$y = \frac{32}{4}$<br /><br />$y = 8$<br /><br />Therefore, the equation has one solution: $y = 8$.<br /><br />7. To solve the equation $3=t+11.5-t$, we need to simplify both sides of the equation and then isolate the variable $t$. <br /><br />$3 = t + 11.5 - t$<br /><br />$3 = 11.5$<br /><br />Since both sides of the equation are equal, this equation has infinitely many solutions.<br /><br />8. To solve the equation $4x+8+6x-5=33$, we need to simplify both sides of the equation and then isolate the variable $x$. <br /><br />$4x + 8 + 6x - 5 = 33$<br /><br />$10x + 3 = 33$<br /><br />$10x = 30$<br /><br />$x = 3$<br /><br />Therefore, the equation has one solution: $x = 3$.<br /><br />9. To solve the equation $5(2c+7)-3c=7(c+5)$, we need to simplify both sides of the equation and then isolate the variable $c$. <br /><br />$5(2c+7) - 3c = 7(c+5)$<br /><br />$10c + 35 - 3c = 7c + 35$<br /><br />$7c + 35 = 7c + 35$<br /><br />Since both sides of the equation are equal, this equation has infinitely many solutions.<br /><br />10. To solve the equation $\frac{3}{2}b+6+\frac{1}{2}b=15+2b$, we need to simplify both sides of the equation and then isolate the variable $b$. <br /><br />$\frac{3}{2}b + 6 + \frac{1}{2}b = 15 + 2b$<br /><br />$2b + 6 = 15 + 2b$<br /><br />$6 = 15$<br /><br />Since both sides of the equation are equal, this equation has infinitely many solutions.