For the following system use the second equation to make a substitution for xin the first equation. 3x+2y=7 x-y+3=0 What is the resulting equation? 3y-3+2y=7 3(y-3)+2y=7 3x-y-3+2y=7

To solve this problem, we need to use the second equation to make a substitution for x in the first equation.<br /><br />Given:<br />$3x + 2y = 7$<br />$x - y + 3 = 0$<br /><br />Step 1: Solve the second equation for x.<br />$x - y + 3 = 0$<br />$x = y - 3$<br /><br />Step 2: Substitute the expression for x into the first equation.<br />$3x + 2y = 7$<br />$3(y - 3) + 2y = 7$<br />$3y - 9 + 2y = 7$<br />$5y - 9 = 7$<br />$5y = 16$<br />$y = \frac{16}{5}$<br /><br />Step 3: Substitute the value of y back into the expression for x.<br />$x = y - 3$<br />$x = \frac{16}{5} - 3$<br />$x = \frac{16}{5} - \frac{15}{5}$<br />$x = \frac{1}{5}$<br /><br />Therefore, the resulting equation is:<br />$3x - y - 3 + 2y = 7$<br />$3x + y - 3 = 7$<br />$3x + y = 10$<br />$3x = 10 - y$<br />$x = \frac{10 - y}{3}$<br /><br />So, the correct answer is:<br />$3x - y - 3 + 2y = 7$