Solve. sqrt [3](6y-1)+5=10 y=square

To solve the equation, we first isolate the cube root term by subtracting 5 from both sides of the equation:<br /><br />$\sqrt [3]{6y-1}+5-5=10-5$<br /><br />This simplifies to:<br /><br />$\sqrt [3]{6y-1}=5$<br /><br />Next, we cube both sides of the equation to eliminate the cube root:<br /><br />$(\sqrt [3]{6y-1})^3=5^3$<br /><br />This simplifies to:<br /><br />$6y-1=125$<br /><br />Next, we add 1 to both sides of the equation to isolate the term with y:<br /><br />$6y-1+1=125+1$<br /><br />This simplifies to:<br /><br />$6y=126$<br /><br />Finally, we divide both sides of the equation by 6 to solve for y:<br /><br />$y=\frac{126}{6}$<br /><br />This simplifies to:<br /><br />$y=21$<br /><br />So, the solution to the equation is $y=21$.