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6. x^2-10x+16"
FACTOR each problem as demonstrated in class. Show All WORK! 6. x^2-10x+16
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Nadiaveterano · Tutor durante 11 años
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<br /><br />To factor the quadratic expression $x^{2}-10x+16$, we need to find two numbers that multiply to 16 (the constant term) and add up to -10 (the coefficient of the linear term).<br /><br />Let's list the pairs of factors of 16:<br /><br />1. $1 \times 16$<br />2. $2 \times 8$<br />3. $4 \times 4$<br /><br />Now, let's check which pair adds up to -10:<br /><br />1. $1 + 16 = 17$<br />2. $2 + 8 = 10$<br />3. $4 + 4 = 8$<br /><br />We can see that none of the pairs of factors of 16 add up to -10. This means that the quadratic expression $x^{2}-10x+16$ cannot be factored using integers.<br /><br />Therefore, the factored form of $x^{2}-10x+16$ is $\boxed{x^{2}-10x+16}$.
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