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Convert Log Equation to Exponential (Numeric) Question Write the logarithmic equation as an exponential equation. log_(7)((1)/(343))=-3 Answer Attemptiout of 2 square
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Miguelmaestro · Tutor durante 5 años
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4.0 (299 votos)
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\(7^{-3} = \frac {1}{343}\)
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## Step 1<br />The given equation is in logarithmic form: \(log_{7}(\frac {1}{343})=-3\). The base of the logarithm is 7, the argument of the logarithm is \(\frac {1}{343}\), and the value of the logarithm is -3.<br /><br />## Step 2<br />To convert this logarithmic equation into an exponential equation, we use the definition of a logarithm. The definition of a logarithm states that if \(log_{b}a = c\), then \(b^c = a\).<br /><br />## Step 3<br />Applying this definition to our given equation, we get \(7^{-3} = \frac {1}{343}\).
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