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
Use substitution to determine whether the plven x-value is a solution of the equation. sinx=(sqrt (2))/(2),x=(pi )/(6) x=(pi )/(6) is not a solution of the equation. x=(pi )/(6) is a solution of the equation.
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\(x=\frac{\pi}{6}\) is not a solution of the equation.
Explicar
## Step 1<br />The problem asks us to determine whether the given x-value, \(x=\frac{\pi}{6}\), is a solution to the equation \(sinx=\frac{\sqrt{2}}{2}\). To do this, we substitute \(x=\frac{\pi}{6}\) into the equation and check if the equation holds true.<br /><br />## Step 2<br />The sine of \(\frac{\pi}{6}\) is \(\frac{1}{2}\), which is not equal to \(\frac{\sqrt{2}}{2}\). Therefore, \(x=\frac{\pi}{6}\) is not a solution to the equation.
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