The number of grams of a radioactive isotope present after t years is 1,500((1)/(2))^t What does 1,500 represent in this situation if tgt 0 A. the original number of grams of the radioactive isotope present B. the number of grams of the radioactive isotope present after (1)/(2) year C. the number of grams of the radioactive isotope present after 2 years D. the final number of grams of the radioactive isotope present

<br />The given function is $1,500(\frac {1}{2})^{t}$. In this function, the number 1,500 is the initial amount of the radioactive isotope present before any decay has occurred. This is because when $t=0$, the function simplifies to $1,500(\frac {1}{2})^{0}=1,500*1=1,500$. This means that when $t=0$, there are 1,500 grams of the radioactive isotope present. <br /><br />So, the number 1,500 in this situation represents the original number of grams of the radioactive isotope present. <br /><br />Therefore, the correct answer is A. the original number of grams of the radioactive isotope present.