Find the 73rd term of the arithmetic sequence -28,-41,-54,ldots Answer Attemptiout of square

To find the 73rd term of the arithmetic sequence, we first need to determine the common difference between consecutive terms.<br /><br />Given the sequence: $-28, -41, -54, \ldots$<br /><br />The common difference, $d$, can be found by subtracting any term from the term that follows it:<br />$d = -41 - (-28) = -41 + 28 = -13$<br /><br />Now, we can use the formula for the $n$th term of an arithmetic sequence:<br />$a_n = a_1 + (n-1)d$<br /><br />Where:<br />- $a_n$ is the $n$<br />- $a_1$ is the first term<br />- $n$ is the term number<br />- $d$ is the common difference<br /><br />Substituting the values we have:<br />$a_{73} = -28 + (73-1)(-13)$<br />$a_{73} = -28 + 72(-13)$<br />$a_{73} = -28 - 936$<br />$a_{73} = -964$<br /><br />Therefore, the 73rd term of the arithmetic sequence is $\boxed{-964}$.